例 5.2.4easy一级题目发布者: ai-batch题干考察例 5.2.1 的样本(20 名青年人某月的娱乐支出费用数据): 790840840880920930940970980990790 \quad 840 \quad 840 \quad 880 \quad 920 \quad 930 \quad 940 \quad 970 \quad 980 \quad 990790840840880920930940970980990 10001010101010201020108011001130118012501000 \quad 1010 \quad 1010 \quad 1020 \quad 1020 \quad 1080 \quad 1100 \quad 1130 \quad 1180 \quad 12501000101010101020102010801100113011801250 已知样本均值 xˉ=994\bar{x} = 994xˉ=994,求该样本的样本方差 s2s^2s2 与样本标准差 sss。答案点击展开后可查看解析解析样本方差为 s2=120−1[(790−994)2+(840−994)2+⋯+(1250−994)2]=13 393.68,s^2 = \frac{1}{20-1}\left[(790-994)^2 + (840-994)^2 + \cdots + (1250-994)^2\right] = 13\,393.68,s2=20−11[(790−994)2+(840−994)2+⋯+(1250−994)2]=13393.68, 样本标准差为 s=13 393.68=115.731.s = \sqrt{13\,393.68} = 115.731.s=13393.68=115.731.